Watlow Heater Catalog

Tubular Heaters WATROD 1- 15

WATROD Single/Double-Ended Heaters Bend Formations (Continued)

Figure 15

Figure 16

A

A

K

Dia.

L

R 1

WATROD 1- 18

R 1

R 2

X Hairpins

B

R 2

X Hairpins

H

R 1

R 1

WATROD 1- 17

H

R 2

R 4

R 2

R 1

R 1

R 3

L

Dia.

X = Number of Outside Hairpins SL = 2A + 0.43 DIA (1-2X) + 2L (X-1) + 1.14 R 1 + 1.14 R 2 (X-1) X = number of outside hairpins SL = 2A + 0.43 Dia. (1 - 2X) + 2L (X - 1) + 1.14R 1 + 1.14R 2 (X - 1)

SL = 2K + 2A + 2L(X - 1) + 2B - 0.86 R 3 - 0.86 R 4 + 1.14 R 1 (X) + 1.14 R 2 (X - 1) - 4.86 DIA - ( 2X - 1)0.43 DIA X = Number of Outside Hairpins X = number of outside hairpins SL = 2K + 2A + 2K(X - 1) + 2B - 0.86R 3 - 0.86R 4 + 1.14 1 ( ) . R 2 ( - ) - 4.86 Dia. - (2X - 1) 0.43 Dia.

Figure 18

A

Figure 17

Dia.

A

R 1

R 3

L

R 4

X Hairpins

R 2

R 1

R 1

H

R 2

X Hairpins

R 2

R 1

H

K

R 1

B

R 2

C

R 1

Dia.

L

X = Number of Outside Hairpins SL = 2L + 2K + 2B + 2C(X - 1) - 0.86 R 3 - 0.86 R 4 - 4.86 DIA+ 1.14 R 1 (X) + 1.14 R 2 (X - 1) - (2X - 1)0.43 DIA X = number of outside hairpins SL = 2L + 2K + 2B + 2C (X - 1) - 0.86R 3 - 0.86R 4 - 4.86 Dia. + 1.14R 1 (X) + 1.14R 2 (X - 1) - (2X - 1) 0.43 Dia.

R 3

K

X = Number of Outside Hairpins SL = 1.14 R 2 X-0.88 DIA X-1.14 R 2 -2 DIA + 1.14 R 1 X-0.86 R 3 + 2L X-2L + 2A + 2K X = number of outside hairpins SL = 1.14R 2 X - 0.88 Dia. X - 1.14R 2 - 2 Dia. + . R 1 X -0.86R 3 + 2L X - 2L + A + 2K

65